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1431587445173 is a prime number
BaseRepresentation
bin10100110101010001010…
…000101101100110110101
312001212011210100021020122
4110311101100231212311
5141423342341221143
63013355011141325
7205300033335644
oct24652120554665
95055153307218
101431587445173
11502150878386
121b154b8a4845
13a4cc8b2a332
144d4097db35b
152738b307c68
hex14d5142d9b5

1431587445173 has 2 divisors, whose sum is σ = 1431587445174. Its totient is φ = 1431587445172.

The previous prime is 1431587445161. The next prime is 1431587445187. The reversal of 1431587445173 is 3715447851341.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1253374289764 + 178213155409 = 1119542^2 + 422153^2 .

It is a cyclic number.

It is not a de Polignac number, because 1431587445173 - 24 = 1431587445157 is a prime.

It is a super-2 number, since 2×14315874451732 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1431587445373) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 715793722586 + 715793722587.

It is an arithmetic number, because the mean of its divisors is an integer number (715793722587).

Almost surely, 21431587445173 is an apocalyptic number.

It is an amenable number.

1431587445173 is a deficient number, since it is larger than the sum of its proper divisors (1).

1431587445173 is an equidigital number, since it uses as much as digits as its factorization.

1431587445173 is an evil number, because the sum of its binary digits is even.

The product of its digits is 5644800, while the sum is 53.

The spelling of 1431587445173 in words is "one trillion, four hundred thirty-one billion, five hundred eighty-seven million, four hundred forty-five thousand, one hundred seventy-three".