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143172242951 is a prime number
BaseRepresentation
bin1000010101010110111…
…0110000111000000111
3111200112220211111222212
42011111232300320013
54321204043233301
6145434502014035
713225640662013
oct2052556607007
9450486744885
10143172242951
115579aaa9231
12238b811731b
1310668b6272a
146d02a6d543
153ace48a4bb
hex2155bb0e07

143172242951 has 2 divisors, whose sum is σ = 143172242952. Its totient is φ = 143172242950.

The previous prime is 143172242947. The next prime is 143172242953. The reversal of 143172242951 is 159242271341.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 143172242951 - 22 = 143172242947 is a prime.

Together with 143172242953, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 143172242899 and 143172242908.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (143172242953) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71586121475 + 71586121476.

It is an arithmetic number, because the mean of its divisors is an integer number (71586121476).

Almost surely, 2143172242951 is an apocalyptic number.

143172242951 is a deficient number, since it is larger than the sum of its proper divisors (1).

143172242951 is an equidigital number, since it uses as much as digits as its factorization.

143172242951 is an evil number, because the sum of its binary digits is even.

The product of its digits is 120960, while the sum is 41.

The spelling of 143172242951 in words is "one hundred forty-three billion, one hundred seventy-two million, two hundred forty-two thousand, nine hundred fifty-one".