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143188471841 is a prime number
BaseRepresentation
bin1000010101011010110…
…0101011000000100001
3111200121001101000211212
42011112230223000201
54321222222044331
6145440241515505
713226225633402
oct2052654530041
9450531330755
10143188471841
11557a9183238
1223901642b95
131066c32551c
146d04c959a9
153ad0ae3d2b
hex2156b2b021

143188471841 has 2 divisors, whose sum is σ = 143188471842. Its totient is φ = 143188471840.

The previous prime is 143188471781. The next prime is 143188471843. The reversal of 143188471841 is 148174881341.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 96836104225 + 46352367616 = 311185^2 + 215296^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-143188471841 is a prime.

It is a Sophie Germain prime.

Together with 143188471843, it forms a pair of twin primes.

It is a Chen prime.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 143188471841.

It is not a weakly prime, because it can be changed into another prime (143188471843) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71594235920 + 71594235921.

It is an arithmetic number, because the mean of its divisors is an integer number (71594235921).

Almost surely, 2143188471841 is an apocalyptic number.

It is an amenable number.

143188471841 is a deficient number, since it is larger than the sum of its proper divisors (1).

143188471841 is an equidigital number, since it uses as much as digits as its factorization.

143188471841 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 688128, while the sum is 50.

The spelling of 143188471841 in words is "one hundred forty-three billion, one hundred eighty-eight million, four hundred seventy-one thousand, eight hundred forty-one".