14320201142022 has 32 divisors (see below), whose sum is σ = 28688195500800. Its totient is φ = 4765441107168.

The previous prime is 14320201142021. The next prime is 14320201142033. The reversal of 14320201142022 is 22024110202341.

It is a junction number, because it is equal to n+sod(n) for n = 14320201141983 and 14320201142001.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14320201142021) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 8379804 + ... + 9942912.

It is an arithmetic number, because the mean of its divisors is an integer number (896506109400).

Almost surely, 2^{14320201142022} is an apocalyptic number.

14320201142022 is an abundant number, since it is smaller than the sum of its proper divisors (14367994358778).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

14320201142022 is a wasteful number, since it uses less digits than its factorization.

14320201142022 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1565660.

The product of its (nonzero) digits is 1536, while the sum is 24.

Adding to 14320201142022 its reverse (22024110202341), we get a palindrome (36344311344363).

The spelling of 14320201142022 in words is "fourteen trillion, three hundred twenty billion, two hundred one million, one hundred forty-two thousand, twenty-two".