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143232324133 is a prime number
BaseRepresentation
bin1000010101100101001…
…1111101001000100101
3111200201002212221212211
42011121103331020211
54321314433333013
6145444445443421
713230300444553
oct2053123751045
9450632787784
10143232324133
1155820a050a8
1223914270571
131067843a622
146d0aa2cbd3
153ad48a723d
hex21594fd225

143232324133 has 2 divisors, whose sum is σ = 143232324134. Its totient is φ = 143232324132.

The previous prime is 143232324121. The next prime is 143232324139. The reversal of 143232324133 is 331423232341.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 86908219204 + 56324104929 = 294802^2 + 237327^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-143232324133 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 143232324095 and 143232324104.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (143232324139) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71616162066 + 71616162067.

It is an arithmetic number, because the mean of its divisors is an integer number (71616162067).

Almost surely, 2143232324133 is an apocalyptic number.

It is an amenable number.

143232324133 is a deficient number, since it is larger than the sum of its proper divisors (1).

143232324133 is an equidigital number, since it uses as much as digits as its factorization.

143232324133 is an evil number, because the sum of its binary digits is even.

The product of its digits is 31104, while the sum is 31.

Adding to 143232324133 its reverse (331423232341), we get a palindrome (474655556474).

The spelling of 143232324133 in words is "one hundred forty-three billion, two hundred thirty-two million, three hundred twenty-four thousand, one hundred thirty-three".