Base | Representation |
---|---|
bin | 10100110101111101001… |
… | …011010101001101100111 |
3 | 12001221002010201220211002 |
4 | 110311331023111031213 |
5 | 141431400000411124 |
6 | 3014000051103515 |
7 | 205324221043421 |
oct | 24657513251547 |
9 | 5057063656732 |
10 | 1432324232039 |
11 | 502499763248 |
12 | 1b17165a1b9b |
13 | a50b56798ac |
14 | 4d4795cd811 |
15 | 273d0d450ae |
hex | 14d7d2d5367 |
1432324232039 has 2 divisors, whose sum is σ = 1432324232040. Its totient is φ = 1432324232038.
The previous prime is 1432324231991. The next prime is 1432324232089. The reversal of 1432324232039 is 9302324232341.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1432324232039 - 28 = 1432324231783 is a prime.
It is a super-2 number, since 2×14323242320392 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1432324231993 and 1432324232011.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1432324232089) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 716162116019 + 716162116020.
It is an arithmetic number, because the mean of its divisors is an integer number (716162116020).
Almost surely, 21432324232039 is an apocalyptic number.
1432324232039 is a deficient number, since it is larger than the sum of its proper divisors (1).
1432324232039 is an equidigital number, since it uses as much as digits as its factorization.
1432324232039 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 186624, while the sum is 38.
The spelling of 1432324232039 in words is "one trillion, four hundred thirty-two billion, three hundred twenty-four million, two hundred thirty-two thousand, thirty-nine".
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