Base | Representation |
---|---|
bin | 1101000001101110100100… |
… | …1101010011000001010011 |
3 | 1212201022000202000201122211 |
4 | 3100123221031103001103 |
5 | 3334133141341320341 |
6 | 50244014255012551 |
7 | 3005553362202166 |
oct | 320335115230123 |
9 | 55638022021584 |
10 | 14323333541971 |
11 | 4622545415373 |
12 | 1733b5b50a157 |
13 | 7cb8b8c84a0c |
14 | 3773784c3add |
15 | 19c8b1d04181 |
hex | d06e9353053 |
14323333541971 has 2 divisors, whose sum is σ = 14323333541972. Its totient is φ = 14323333541970.
The previous prime is 14323333541897. The next prime is 14323333542041. The reversal of 14323333541971 is 17914533332341.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14323333541971 - 215 = 14323333509203 is a prime.
It is not a weakly prime, because it can be changed into another prime (14323333541471) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7161666770985 + 7161666770986.
It is an arithmetic number, because the mean of its divisors is an integer number (7161666770986).
Almost surely, 214323333541971 is an apocalyptic number.
14323333541971 is a deficient number, since it is larger than the sum of its proper divisors (1).
14323333541971 is an equidigital number, since it uses as much as digits as its factorization.
14323333541971 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2449440, while the sum is 49.
The spelling of 14323333541971 in words is "fourteen trillion, three hundred twenty-three billion, three hundred thirty-three million, five hundred forty-one thousand, nine hundred seventy-one".
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