14323333542041 has 2 divisors, whose sum is σ = 14323333542042. Its totient is φ = 14323333542040.

The previous prime is 14323333541971. The next prime is 14323333542047. The reversal of 14323333542041 is 14024533332341.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8821963292041 + 5501370250000 = 2970179^2 + 2345500^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14323333542041 is a prime.

It is a super-2 number, since 2×14323333542041² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 14323333541986 and 14323333542004.

It is not a weakly prime, because it can be changed into another prime (14323333542047) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7161666771020 + 7161666771021.

It is an arithmetic number, because the mean of its divisors is an integer number (7161666771021).

Almost surely, 2^{14323333542041} is an apocalyptic number.

It is an amenable number.

14323333542041 is a deficient number, since it is larger than the sum of its proper divisors (1).

14323333542041 is an equidigital number, since it uses as much as digits as its factorization.

14323333542041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 311040, while the sum is 38.

Adding to 14323333542041 its reverse (14024533332341), we get a palindrome (28347866874382).

The spelling of 14323333542041 in words is "fourteen trillion, three hundred twenty-three billion, three hundred thirty-three million, five hundred forty-two thousand, forty-one".