Base | Representation |
---|---|
bin | 1101000001101110100100… |
… | …1101010011000010010011 |
3 | 1212201022000202000201202012 |
4 | 3100123221031103002103 |
5 | 3334133141341321120 |
6 | 50244014255013135 |
7 | 3005553362202320 |
oct | 320335115230223 |
9 | 55638022021665 |
10 | 14323333542035 |
11 | 4622545415421 |
12 | 1733b5b50a1ab |
13 | 7cb8b8c84a5b |
14 | 3773784c3b47 |
15 | 19c8b1d041c5 |
hex | d06e9353093 |
14323333542035 has 32 divisors (see below), whose sum is σ = 20431874985984. Its totient is φ = 9432328464000.
The previous prime is 14323333541971. The next prime is 14323333542041. The reversal of 14323333542035 is 53024533332341.
It is not a de Polignac number, because 14323333542035 - 26 = 14323333541971 is a prime.
It is a super-2 number, since 2×143233335420352 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 14323333541983 and 14323333542001.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 50244236 + ... + 50528505.
It is an arithmetic number, because the mean of its divisors is an integer number (638496093312).
Almost surely, 214323333542035 is an apocalyptic number.
14323333542035 is a deficient number, since it is larger than the sum of its proper divisors (6108541443949).
14323333542035 is a wasteful number, since it uses less digits than its factorization.
14323333542035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 100772915.
The product of its (nonzero) digits is 1166400, while the sum is 41.
Adding to 14323333542035 its reverse (53024533332341), we get a palindrome (67347866874376).
The spelling of 14323333542035 in words is "fourteen trillion, three hundred twenty-three billion, three hundred thirty-three million, five hundred forty-two thousand, thirty-five".
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