Base | Representation |
---|---|
bin | 1101000001101110100110… |
… | …0111100100111010000111 |
3 | 1212201022001012222201121102 |
4 | 3100123221213210322013 |
5 | 3334133200122242413 |
6 | 50244015102410315 |
7 | 3005553504563603 |
oct | 320335147447207 |
9 | 55638035881542 |
10 | 14323340430983 |
11 | 46225492a0171 |
12 | 1733b6189099b |
13 | 7cb8ba52755c |
14 | 377379398503 |
15 | 19c8b2715458 |
hex | d06e99e4e87 |
14323340430983 has 2 divisors, whose sum is σ = 14323340430984. Its totient is φ = 14323340430982.
The previous prime is 14323340430953. The next prime is 14323340431019. The reversal of 14323340430983 is 38903404332341.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14323340430983 - 216 = 14323340365447 is a prime.
It is a super-2 number, since 2×143233404309832 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14323340430923) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7161670215491 + 7161670215492.
It is an arithmetic number, because the mean of its divisors is an integer number (7161670215492).
Almost surely, 214323340430983 is an apocalyptic number.
14323340430983 is a deficient number, since it is larger than the sum of its proper divisors (1).
14323340430983 is an equidigital number, since it uses as much as digits as its factorization.
14323340430983 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2239488, while the sum is 47.
The spelling of 14323340430983 in words is "fourteen trillion, three hundred twenty-three billion, three hundred forty million, four hundred thirty thousand, nine hundred eighty-three".
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