Base | Representation |
---|---|
bin | 1000010101100110000… |
… | …0010001000001011001 |
3 | 111200201022221220202022 |
4 | 2011121200101001121 |
5 | 4321321300120241 |
6 | 145445042544225 |
7 | 13230340045352 |
oct | 2053140210131 |
9 | 450638856668 |
10 | 143235551321 |
11 | 558228097a5 |
12 | 23915368075 |
13 | 10678cca4c5 |
14 | 6d0b22cd29 |
15 | 3ad4ce354b |
hex | 2159811059 |
143235551321 has 2 divisors, whose sum is σ = 143235551322. Its totient is φ = 143235551320.
The previous prime is 143235551299. The next prime is 143235551323. The reversal of 143235551321 is 123155532341.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 127563265600 + 15672285721 = 357160^2 + 125189^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-143235551321 is a prime.
Together with 143235551323, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (143235551323) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71617775660 + 71617775661.
It is an arithmetic number, because the mean of its divisors is an integer number (71617775661).
Almost surely, 2143235551321 is an apocalyptic number.
It is an amenable number.
143235551321 is a deficient number, since it is larger than the sum of its proper divisors (1).
143235551321 is an equidigital number, since it uses as much as digits as its factorization.
143235551321 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 54000, while the sum is 35.
The spelling of 143235551321 in words is "one hundred forty-three billion, two hundred thirty-five million, five hundred fifty-one thousand, three hundred twenty-one".
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