Base | Representation |
---|---|
bin | 1101000001110101001111… |
… | …1100101010100110101111 |
3 | 1212201110122112201220112202 |
4 | 3100131103330222212233 |
5 | 3334200323313003424 |
6 | 50244512110052115 |
7 | 3005645635601102 |
oct | 320352374524657 |
9 | 55643575656482 |
10 | 14325124344239 |
11 | 4623284267645 |
12 | 173437b1aa03b |
13 | 7cbb12ca4427 |
14 | 3774a8284739 |
15 | 19c9691422ae |
hex | d0753f2a9af |
14325124344239 has 2 divisors, whose sum is σ = 14325124344240. Its totient is φ = 14325124344238.
The previous prime is 14325124344173. The next prime is 14325124344263. The reversal of 14325124344239 is 93244342152341.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14325124344239 - 212 = 14325124340143 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 14325124344193 and 14325124344202.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14325154344239) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7162562172119 + 7162562172120.
It is an arithmetic number, because the mean of its divisors is an integer number (7162562172120).
Almost surely, 214325124344239 is an apocalyptic number.
14325124344239 is a deficient number, since it is larger than the sum of its proper divisors (1).
14325124344239 is an equidigital number, since it uses as much as digits as its factorization.
14325124344239 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 2488320, while the sum is 47.
The spelling of 14325124344239 in words is "fourteen trillion, three hundred twenty-five billion, one hundred twenty-four million, three hundred forty-four thousand, two hundred thirty-nine".
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