14325133313111 has 2 divisors, whose sum is σ = 14325133313112. Its totient is φ = 14325133313110.

The previous prime is 14325133313093. The next prime is 14325133313297. The reversal of 14325133313111 is 11131333152341.

14325133313111 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14325133313111 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14325133312111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7162566656555 + 7162566656556.

It is an arithmetic number, because the mean of its divisors is an integer number (7162566656556).

Almost surely, 2^{14325133313111} is an apocalyptic number.

14325133313111 is a deficient number, since it is larger than the sum of its proper divisors (1).

14325133313111 is an equidigital number, since it uses as much as digits as its factorization.

14325133313111 is an evil number, because the sum of its binary digits is even.

The product of its digits is 9720, while the sum is 32.

Adding to 14325133313111 its reverse (11131333152341), we get a palindrome (25456466465452).

The spelling of 14325133313111 in words is "fourteen trillion, three hundred twenty-five billion, one hundred thirty-three million, three hundred thirteen thousand, one hundred eleven".