Base | Representation |
---|---|
bin | 1000010101101001110… |
… | …0110100110001010111 |
3 | 111200202102211110020212 |
4 | 2011122130310301113 |
5 | 4321334331121031 |
6 | 145450411120035 |
7 | 13230622014353 |
oct | 2053234646127 |
9 | 450672743225 |
10 | 143251426391 |
11 | 55830771997 |
12 | 2391a74301b |
13 | 1067c398238 |
14 | 6d0d3a2463 |
15 | 3ad63cc12b |
hex | 215a734c57 |
143251426391 has 2 divisors, whose sum is σ = 143251426392. Its totient is φ = 143251426390.
The previous prime is 143251426337. The next prime is 143251426429. The reversal of 143251426391 is 193624152341.
It is a happy number.
143251426391 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 143251426391 - 214 = 143251410007 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (143251426301) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71625713195 + 71625713196.
It is an arithmetic number, because the mean of its divisors is an integer number (71625713196).
Almost surely, 2143251426391 is an apocalyptic number.
143251426391 is a deficient number, since it is larger than the sum of its proper divisors (1).
143251426391 is an equidigital number, since it uses as much as digits as its factorization.
143251426391 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 155520, while the sum is 41.
The spelling of 143251426391 in words is "one hundred forty-three billion, two hundred fifty-one million, four hundred twenty-six thousand, three hundred ninety-one".
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