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14327011310477 is a prime number
BaseRepresentation
bin1101000001111100010001…
…1010110111101110001101
31212201122112001101201121012
43100133010122313232031
53334213204343413402
650245423234215005
73006043460544305
oct320370432675615
955648461351535
1014327011310477
114624062420278
121734807124465
137cc053bc35b8
14377606b18605
1519ca29b28452
hexd07c46b7b8d

14327011310477 has 2 divisors, whose sum is σ = 14327011310478. Its totient is φ = 14327011310476.

The previous prime is 14327011310471. The next prime is 14327011310483. The reversal of 14327011310477 is 77401311072341.

It is a balanced prime because it is at equal distance from previous prime (14327011310471) and next prime (14327011310483).

It can be written as a sum of positive squares in only one way, i.e., 13729588979716 + 597422330761 = 3705346^2 + 772931^2 .

It is a cyclic number.

It is not a de Polignac number, because 14327011310477 - 24 = 14327011310461 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14327011310471) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7163505655238 + 7163505655239.

It is an arithmetic number, because the mean of its divisors is an integer number (7163505655239).

Almost surely, 214327011310477 is an apocalyptic number.

It is an amenable number.

14327011310477 is a deficient number, since it is larger than the sum of its proper divisors (1).

14327011310477 is an equidigital number, since it uses as much as digits as its factorization.

14327011310477 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 98784, while the sum is 41.

The spelling of 14327011310477 in words is "fourteen trillion, three hundred twenty-seven billion, eleven million, three hundred ten thousand, four hundred seventy-seven".