Base | Representation |
---|---|
bin | 1101000001111100010001… |
… | …1010110111101110001101 |
3 | 1212201122112001101201121012 |
4 | 3100133010122313232031 |
5 | 3334213204343413402 |
6 | 50245423234215005 |
7 | 3006043460544305 |
oct | 320370432675615 |
9 | 55648461351535 |
10 | 14327011310477 |
11 | 4624062420278 |
12 | 1734807124465 |
13 | 7cc053bc35b8 |
14 | 377606b18605 |
15 | 19ca29b28452 |
hex | d07c46b7b8d |
14327011310477 has 2 divisors, whose sum is σ = 14327011310478. Its totient is φ = 14327011310476.
The previous prime is 14327011310471. The next prime is 14327011310483. The reversal of 14327011310477 is 77401311072341.
It is a balanced prime because it is at equal distance from previous prime (14327011310471) and next prime (14327011310483).
It can be written as a sum of positive squares in only one way, i.e., 13729588979716 + 597422330761 = 3705346^2 + 772931^2 .
It is a cyclic number.
It is not a de Polignac number, because 14327011310477 - 24 = 14327011310461 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14327011310471) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7163505655238 + 7163505655239.
It is an arithmetic number, because the mean of its divisors is an integer number (7163505655239).
Almost surely, 214327011310477 is an apocalyptic number.
It is an amenable number.
14327011310477 is a deficient number, since it is larger than the sum of its proper divisors (1).
14327011310477 is an equidigital number, since it uses as much as digits as its factorization.
14327011310477 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 98784, while the sum is 41.
The spelling of 14327011310477 in words is "fourteen trillion, three hundred twenty-seven billion, eleven million, three hundred ten thousand, four hundred seventy-seven".
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