Base | Representation |
---|---|
bin | 1000010101111000010… |
… | …1100100101111111111 |
3 | 111200220200122021121222 |
4 | 2011132011210233333 |
5 | 4322000441042234 |
6 | 145500430543555 |
7 | 13232262433466 |
oct | 2053605445777 |
9 | 450820567558 |
10 | 143312440319 |
11 | 55862155624 |
12 | 23937067bbb |
13 | 1068bc0b859 |
14 | 6d175259dd |
15 | 3adb93042e |
hex | 215e164bff |
143312440319 has 2 divisors, whose sum is σ = 143312440320. Its totient is φ = 143312440318.
The previous prime is 143312440273. The next prime is 143312440321. The reversal of 143312440319 is 913044213341.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 143312440319 - 224 = 143295663103 is a prime.
It is a super-2 number, since 2×1433124403192 (a number of 23 digits) contains 22 as substring.
Together with 143312440321, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (143312440339) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71656220159 + 71656220160.
It is an arithmetic number, because the mean of its divisors is an integer number (71656220160).
Almost surely, 2143312440319 is an apocalyptic number.
143312440319 is a deficient number, since it is larger than the sum of its proper divisors (1).
143312440319 is an equidigital number, since it uses as much as digits as its factorization.
143312440319 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 31104, while the sum is 35.
The spelling of 143312440319 in words is "one hundred forty-three billion, three hundred twelve million, four hundred forty thousand, three hundred nineteen".
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