Base | Representation |
---|---|
bin | 11010101100011011… |
… | …01110010011110111 |
3 | 1100222202221111122020 |
4 | 31112031232103313 |
5 | 213322310340043 |
6 | 10330030204223 |
7 | 1015100244300 |
oct | 152615562367 |
9 | 40882844566 |
10 | 14331340023 |
11 | 6094738970 |
12 | 293b653673 |
13 | 1475160870 |
14 | 99d4c77a7 |
15 | 58d282e83 |
hex | 35636e4f7 |
14331340023 has 48 divisors (see below), whose sum is σ = 26114288256. Its totient is φ = 6872160960.
The previous prime is 14331340013. The next prime is 14331340057. The reversal of 14331340023 is 32004313341.
It is not a de Polignac number, because 14331340023 - 210 = 14331338999 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 14331339975 and 14331340002.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14331340013) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 319861 + ... + 361902.
It is an arithmetic number, because the mean of its divisors is an integer number (544047672).
Almost surely, 214331340023 is an apocalyptic number.
14331340023 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
14331340023 is a deficient number, since it is larger than the sum of its proper divisors (11782948233).
14331340023 is a wasteful number, since it uses less digits than its factorization.
14331340023 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 681804 (or 681797 counting only the distinct ones).
The product of its (nonzero) digits is 2592, while the sum is 24.
Adding to 14331340023 its reverse (32004313341), we get a palindrome (46335653364).
The spelling of 14331340023 in words is "fourteen billion, three hundred thirty-one million, three hundred forty thousand, twenty-three".
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