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1433142401050 = 25254715239051
BaseRepresentation
bin10100110110101101111…
…100011001100000011010
312002000012011021012201001
4110312231330121200122
5141440033423313200
63014213155215214
7205353414262003
oct24665574314032
95060164235631
101433142401050
11502879583788
121b19045a750a
13a51b6021679
144d5161281aa
152742caaa76a
hex14dadf1981a

1433142401050 has 24 divisors (see below), whose sum is σ = 2666132606592. Its totient is φ = 573152070000.

The previous prime is 1433142401011. The next prime is 1433142401057. The reversal of 1433142401050 is 501042413341.

It is a super-2 number, since 2×14331424010502 (a number of 25 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (1433142401057) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 2345976 + ... + 2893075.

It is an arithmetic number, because the mean of its divisors is an integer number (111088858608).

Almost surely, 21433142401050 is an apocalyptic number.

1433142401050 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1433142401050 is a deficient number, since it is larger than the sum of its proper divisors (1232990205542).

1433142401050 is a wasteful number, since it uses less digits than its factorization.

1433142401050 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5244534 (or 5244529 counting only the distinct ones).

The product of its (nonzero) digits is 5760, while the sum is 28.

Adding to 1433142401050 its reverse (501042413341), we get a palindrome (1934184814391).

The spelling of 1433142401050 in words is "one trillion, four hundred thirty-three billion, one hundred forty-two million, four hundred one thousand, fifty".

Divisors: 1 2 5 10 25 50 5471 10942 27355 54710 136775 273550 5239051 10478102 26195255 52390510 130976275 261952550 28662848021 57325696042 143314240105 286628480210 716571200525 1433142401050