Base | Representation |
---|---|
bin | 11010101100011100… |
… | …00101010010000111 |
3 | 1100222210010021201021 |
4 | 31112032011102013 |
5 | 213322321342434 |
6 | 10330032212011 |
7 | 1015101115522 |
oct | 152616052207 |
9 | 40883107637 |
10 | 14331434119 |
11 | 60947a2632 |
12 | 293b69a007 |
13 | 1475194642 |
14 | 99d50dbb9 |
15 | 58d2a0cb4 |
hex | 356385487 |
14331434119 has 2 divisors, whose sum is σ = 14331434120. Its totient is φ = 14331434118.
The previous prime is 14331434099. The next prime is 14331434141. The reversal of 14331434119 is 91143413341.
It is a weak prime.
It is an emirp because it is prime and its reverse (91143413341) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14331434119 is a prime.
It is a super-2 number, since 2×143314341192 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14331434149) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7165717059 + 7165717060.
It is an arithmetic number, because the mean of its divisors is an integer number (7165717060).
Almost surely, 214331434119 is an apocalyptic number.
14331434119 is a deficient number, since it is larger than the sum of its proper divisors (1).
14331434119 is an equidigital number, since it uses as much as digits as its factorization.
14331434119 is an evil number, because the sum of its binary digits is even.
The product of its digits is 15552, while the sum is 34.
It can be divided in two parts, 14 and 331434119, that added together give a palindrome (331434133).
The spelling of 14331434119 in words is "fourteen billion, three hundred thirty-one million, four hundred thirty-four thousand, one hundred nineteen".
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