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143342055553661 is a prime number
BaseRepresentation
bin100000100101111001101100…
…010011010111101001111101
3200210112100220022101022210222
4200211321230103113221331
5122242004012210204121
61224510233052111125
742123056522546246
oct4045715423275175
9623470808338728
10143342055553661
114174502a493138
12140b07984654a5
1361ca136c49ca3
142757b148cdccd
1511889c85ae0ab
hex825e6c4d7a7d

143342055553661 has 2 divisors, whose sum is σ = 143342055553662. Its totient is φ = 143342055553660.

The previous prime is 143342055553577. The next prime is 143342055553673. The reversal of 143342055553661 is 166355550243341.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 141165147114436 + 2176908439225 = 11881294^2 + 1475435^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-143342055553661 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (143342055553691) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71671027776830 + 71671027776831.

It is an arithmetic number, because the mean of its divisors is an integer number (71671027776831).

Almost surely, 2143342055553661 is an apocalyptic number.

It is an amenable number.

143342055553661 is a deficient number, since it is larger than the sum of its proper divisors (1).

143342055553661 is an equidigital number, since it uses as much as digits as its factorization.

143342055553661 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 19440000, while the sum is 53.

The spelling of 143342055553661 in words is "one hundred forty-three trillion, three hundred forty-two billion, fifty-five million, five hundred fifty-three thousand, six hundred sixty-one".