143345303543341 has 2 divisors, whose sum is σ = 143345303543342. Its totient is φ = 143345303543340.

The previous prime is 143345303543317. The next prime is 143345303543359.

143345303543341 is nontrivially palindromic in base 10.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 128698723946116 + 14646579597225 = 11344546^2 + 3827085^2 .

It is a palprime.

It is a cyclic number.

It is not a de Polignac number, because 143345303543341 - 2¹³ = 143345303535149 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 143345303543291 and 143345303543300.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (143345303543311) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71672651771670 + 71672651771671.

It is an arithmetic number, because the mean of its divisors is an integer number (71672651771671).

Almost surely, 2^{143345303543341} is an apocalyptic number.

It is an amenable number.

143345303543341 is a deficient number, since it is larger than the sum of its proper divisors (1).

143345303543341 is an equidigital number, since it uses as much as digits as its factorization.

143345303543341 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4665600, while the sum is 46.

It can be divided in two parts, 14334530 and 3543341, that added together give a palindrome (17877871).

The spelling of 143345303543341 in words is "one hundred forty-three trillion, three hundred forty-five billion, three hundred three million, five hundred forty-three thousand, three hundred forty-one".