Base | Representation |
---|---|
bin | 100000100101111100101101… |
… | …111001011101111000101110 |
3 | 200210112200021200001022001002 |
4 | 200211330231321131320232 |
5 | 122242032140201341332 |
6 | 1224511531235520302 |
7 | 42123233152162025 |
oct | 4045745571357056 |
9 | 623480250038032 |
10 | 143345303543342 |
11 | 4174644693392a |
12 | 140b1344159092 |
13 | 61ca533b1bb84 |
14 | 2757d4200b8bc |
15 | 1188b187db562 |
hex | 825f2de5de2e |
143345303543342 has 4 divisors (see below), whose sum is σ = 215017955315016. Its totient is φ = 71672651771670.
The previous prime is 143345303543341. The next prime is 143345303543359. The reversal of 143345303543342 is 243345303543341.
It is a semiprime because it is the product of two primes.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (143345303543341) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 35836325885834 + ... + 35836325885837.
It is an arithmetic number, because the mean of its divisors is an integer number (53754488828754).
Almost surely, 2143345303543342 is an apocalyptic number.
143345303543342 is a deficient number, since it is larger than the sum of its proper divisors (71672651771674).
143345303543342 is an equidigital number, since it uses as much as digits as its factorization.
143345303543342 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 71672651771673.
The product of its (nonzero) digits is 9331200, while the sum is 47.
Subtracting 143345303543342 from its reverse (243345303543341), we obtain a palindrome (99999999999999).
The spelling of 143345303543342 in words is "one hundred forty-three trillion, three hundred forty-five billion, three hundred three million, five hundred forty-three thousand, three hundred forty-two".
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