Base | Representation |
---|---|
bin | 1000010110000000011… |
… | …0111111100010110001 |
3 | 111201000001110220210102 |
4 | 2011200012333202301 |
5 | 4322033132213031 |
6 | 145504042042145 |
7 | 13233154004162 |
oct | 2054006774261 |
9 | 451001426712 |
10 | 143346366641 |
11 | 5587a317a05 |
12 | 239464a9355 |
13 | 10695c599ba |
14 | 6d1bc37769 |
15 | 3ade8d27cb |
hex | 21601bf8b1 |
143346366641 has 2 divisors, whose sum is σ = 143346366642. Its totient is φ = 143346366640.
The previous prime is 143346366523. The next prime is 143346366643. The reversal of 143346366641 is 146663643341.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 128776911025 + 14569455616 = 358855^2 + 120704^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-143346366641 is a prime.
Together with 143346366643, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (143346366643) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71673183320 + 71673183321.
It is an arithmetic number, because the mean of its divisors is an integer number (71673183321).
Almost surely, 2143346366641 is an apocalyptic number.
It is an amenable number.
143346366641 is a deficient number, since it is larger than the sum of its proper divisors (1).
143346366641 is an equidigital number, since it uses as much as digits as its factorization.
143346366641 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 2239488, while the sum is 47.
The spelling of 143346366641 in words is "one hundred forty-three billion, three hundred forty-six million, three hundred sixty-six thousand, six hundred forty-one".
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