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14339121018659 is a prime number
BaseRepresentation
bin1101000010101001011000…
…1101101111011100100011
31212202210202222221122021122
43100222112031233130203
53334413004440044114
650255145023242455
73006652533426053
oct320522615573443
955683688848248
1014339121018659
114629206aa4268
12173702674942b
138002339ba6b8
14378035133563
1519ced7d19e8e
hexd0a9636f723

14339121018659 has 2 divisors, whose sum is σ = 14339121018660. Its totient is φ = 14339121018658.

The previous prime is 14339121018653. The next prime is 14339121018701. The reversal of 14339121018659 is 95681012193341.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 14339121018659 - 28 = 14339121018403 is a prime.

It is a super-2 number, since 2×143391210186592 (a number of 27 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 14339121018659.

It is not a weakly prime, because it can be changed into another prime (14339121018653) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7169560509329 + 7169560509330.

It is an arithmetic number, because the mean of its divisors is an integer number (7169560509330).

Almost surely, 214339121018659 is an apocalyptic number.

14339121018659 is a deficient number, since it is larger than the sum of its proper divisors (1).

14339121018659 is an equidigital number, since it uses as much as digits as its factorization.

14339121018659 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1399680, while the sum is 53.

The spelling of 14339121018659 in words is "fourteen trillion, three hundred thirty-nine billion, one hundred twenty-one million, eighteen thousand, six hundred fifty-nine".