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1434031555151 = 13110310119627
BaseRepresentation
bin10100110111100010111…
…100010000001001001111
312002002111010100220211102
4110313202330100021033
5141443344034231101
63014441321013315
7205414432046006
oct24674274201117
95062433326742
101434031555151
11503195478388
121b1b1232423b
13a52c82bb460
144d59c25dc3d
1527480b9386b
hex14de2f1024f

1434031555151 has 4 divisors (see below), whose sum is σ = 1544341674792. Its totient is φ = 1323721435512.

The previous prime is 1434031555147. The next prime is 1434031555189. The reversal of 1434031555151 is 1515551304341.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1434031555151 - 22 = 1434031555147 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1434033555151) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 55155059801 + ... + 55155059826.

It is an arithmetic number, because the mean of its divisors is an integer number (386085418698).

Almost surely, 21434031555151 is an apocalyptic number.

1434031555151 is a deficient number, since it is larger than the sum of its proper divisors (110310119641).

1434031555151 is a wasteful number, since it uses less digits than its factorization.

1434031555151 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 110310119640.

The product of its (nonzero) digits is 90000, while the sum is 38.

Adding to 1434031555151 its reverse (1515551304341), we get a palindrome (2949582859492).

The spelling of 1434031555151 in words is "one trillion, four hundred thirty-four billion, thirty-one million, five hundred fifty-five thousand, one hundred fifty-one".

Divisors: 1 13 110310119627 1434031555151