Base | Representation |
---|---|
bin | 10100110111100011000… |
… | …011111000011011001111 |
3 | 12002002111021010112022111 |
4 | 110313203003320123033 |
5 | 141443400042231101 |
6 | 3014441431524451 |
7 | 205414455045631 |
oct | 24674303703317 |
9 | 5062437115274 |
10 | 1434033555151 |
11 | 503196613a7a |
12 | 1b1b12b29727 |
13 | a52c883b8a2 |
14 | 4d59c620a51 |
15 | 27480e3b251 |
hex | 14de30f86cf |
1434033555151 has 2 divisors, whose sum is σ = 1434033555152. Its totient is φ = 1434033555150.
The previous prime is 1434033555137. The next prime is 1434033555191. The reversal of 1434033555151 is 1515553304341.
It is an a-pointer prime, because the next prime (1434033555191) can be obtained adding 1434033555151 to its sum of digits (40).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1434033555151 - 223 = 1434025166543 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1434033555121) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 717016777575 + 717016777576.
It is an arithmetic number, because the mean of its divisors is an integer number (717016777576).
Almost surely, 21434033555151 is an apocalyptic number.
1434033555151 is a deficient number, since it is larger than the sum of its proper divisors (1).
1434033555151 is an equidigital number, since it uses as much as digits as its factorization.
1434033555151 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 270000, while the sum is 40.
Adding to 1434033555151 its reverse (1515553304341), we get a palindrome (2949586859492).
The spelling of 1434033555151 in words is "one trillion, four hundred thirty-four billion, thirty-three million, five hundred fifty-five thousand, one hundred fifty-one".
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