14341180517 has 2 divisors, whose sum is σ = 14341180518. Its totient is φ = 14341180516.

The previous prime is 14341180429. The next prime is 14341180519. The reversal of 14341180517 is 71508114341.

14341180517 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11133204196 + 3207976321 = 105514^2 + 56639^2 .

It is an emirp because it is prime and its reverse (71508114341) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14341180517 - 2⁸ = 14341180261 is a prime.

Together with 14341180519, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14341180519) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7170590258 + 7170590259.

It is an arithmetic number, because the mean of its divisors is an integer number (7170590259).

Almost surely, 2^14341180517 is an apocalyptic number.

It is an amenable number.

14341180517 is a deficient number, since it is larger than the sum of its proper divisors (1).

14341180517 is an equidigital number, since it uses as much as digits as its factorization.

14341180517 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13440, while the sum is 35.

Adding to 14341180517 its reverse (71508114341), we get a palindrome (85849294858).

The spelling of 14341180517 in words is "fourteen billion, three hundred forty-one million, one hundred eighty thousand, five hundred seventeen".