Base | Representation |
---|---|
bin | 1000010110010010000… |
… | …0011000111101010000 |
3 | 111201012012021122111012 |
4 | 2011210200120331100 |
5 | 4322211023230300 |
6 | 145515235110052 |
7 | 13235041006061 |
oct | 2054440307520 |
9 | 451165248435 |
10 | 143420133200 |
11 | 55907a20903 |
12 | 23967142328 |
13 | 106a8316a56 |
14 | 6d2795a568 |
15 | 3ae6104435 |
hex | 2164818f50 |
143420133200 has 60 divisors (see below), whose sum is σ = 344677918368. Its totient is φ = 57349564800.
The previous prime is 143420133193. The next prime is 143420133211. The reversal of 143420133200 is 2331024341.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1220219 + ... + 1332581.
Almost surely, 2143420133200 is an apocalyptic number.
143420133200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
143420133200 is an abundant number, since it is smaller than the sum of its proper divisors (201257785168).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
143420133200 is a wasteful number, since it uses less digits than its factorization.
143420133200 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 115572 (or 115561 counting only the distinct ones).
The product of its (nonzero) digits is 1728, while the sum is 23.
Adding to 143420133200 its reverse (2331024341), we get a palindrome (145751157541).
The spelling of 143420133200 in words is "one hundred forty-three billion, four hundred twenty million, one hundred thirty-three thousand, two hundred".
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