Base | Representation |
---|---|
bin | 1101000010110100011111… |
… | …1011000000000010000111 |
3 | 1212210002110210001001122011 |
4 | 3100231013323000002013 |
5 | 3334440111211402221 |
6 | 50300400525515051 |
7 | 3010116445244446 |
oct | 320550773000207 |
9 | 55702423031564 |
10 | 14342102450311 |
11 | 462a4a6a31a69 |
12 | 1737719112a87 |
13 | 8005ba5a033c |
14 | 3782390a4d5d |
15 | 19d10e9421e1 |
hex | d0b47ec0087 |
14342102450311 has 2 divisors, whose sum is σ = 14342102450312. Its totient is φ = 14342102450310.
The previous prime is 14342102450293. The next prime is 14342102450339. The reversal of 14342102450311 is 11305420124341.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14342102450311 - 213 = 14342102442119 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14342102453311) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7171051225155 + 7171051225156.
It is an arithmetic number, because the mean of its divisors is an integer number (7171051225156).
Almost surely, 214342102450311 is an apocalyptic number.
14342102450311 is a deficient number, since it is larger than the sum of its proper divisors (1).
14342102450311 is an equidigital number, since it uses as much as digits as its factorization.
14342102450311 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 11520, while the sum is 31.
Adding to 14342102450311 its reverse (11305420124341), we get a palindrome (25647522574652).
The spelling of 14342102450311 in words is "fourteen trillion, three hundred forty-two billion, one hundred two million, four hundred fifty thousand, three hundred eleven".
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