Base | Representation |
---|---|
bin | 1101000010110100011111… |
… | …1011000000100001001111 |
3 | 1212210002110210001011100221 |
4 | 3100231013323000201033 |
5 | 3334440111211433203 |
6 | 50300400525532211 |
7 | 3010116445253323 |
oct | 320550773004117 |
9 | 55702423034327 |
10 | 14342102452303 |
11 | 462a4a6a3350a |
12 | 1737719114067 |
13 | 8005ba5a1212 |
14 | 3782390a5983 |
15 | 19d10e942abd |
hex | d0b47ec084f |
14342102452303 has 2 divisors, whose sum is σ = 14342102452304. Its totient is φ = 14342102452302.
The previous prime is 14342102452199. The next prime is 14342102452357. The reversal of 14342102452303 is 30325420124341.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14342102452303 - 217 = 14342102321231 is a prime.
It is a super-3 number, since 3×143421024523033 (a number of 40 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14342102452003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7171051226151 + 7171051226152.
It is an arithmetic number, because the mean of its divisors is an integer number (7171051226152).
Almost surely, 214342102452303 is an apocalyptic number.
14342102452303 is a deficient number, since it is larger than the sum of its proper divisors (1).
14342102452303 is an equidigital number, since it uses as much as digits as its factorization.
14342102452303 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 69120, while the sum is 34.
Adding to 14342102452303 its reverse (30325420124341), we get a palindrome (44667522576644).
The spelling of 14342102452303 in words is "fourteen trillion, three hundred forty-two billion, one hundred two million, four hundred fifty-two thousand, three hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •