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1434304403011 is a prime number
BaseRepresentation
bin10100110111110011001…
…101000101011001000011
312002010012010210000201201
4110313303031011121003
5141444423411344021
63014524345042031
7205424254160554
oct24676315053103
95063163700651
101434304403011
11503315496a87
121b1b89786317
13a533c9a05ac
144d5c65a632b
1527499adc591
hex14df3345643

1434304403011 has 2 divisors, whose sum is σ = 1434304403012. Its totient is φ = 1434304403010.

The previous prime is 1434304403009. The next prime is 1434304403053. The reversal of 1434304403011 is 1103044034341.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1434304403011 - 21 = 1434304403009 is a prime.

It is a super-2 number, since 2×14343044030112 (a number of 25 digits) contains 22 as substring.

Together with 1434304403009, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (1434304403711) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 717152201505 + 717152201506.

It is an arithmetic number, because the mean of its divisors is an integer number (717152201506).

Almost surely, 21434304403011 is an apocalyptic number.

1434304403011 is a deficient number, since it is larger than the sum of its proper divisors (1).

1434304403011 is an equidigital number, since it uses as much as digits as its factorization.

1434304403011 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6912, while the sum is 28.

Adding to 1434304403011 its reverse (1103044034341), we get a palindrome (2537348437352).

The spelling of 1434304403011 in words is "one trillion, four hundred thirty-four billion, three hundred four million, four hundred three thousand, eleven".