Base | Representation |
---|---|
bin | 10100110111111000111… |
… | …110110011000100000111 |
3 | 12002010102220010222112010 |
4 | 110313320332303010013 |
5 | 142000123214234343 |
6 | 3014542130225303 |
7 | 205426542026133 |
oct | 24677076630407 |
9 | 5063386128463 |
10 | 1434401321223 |
11 | 503365173082 |
12 | 1b1bb6125233 |
13 | a5356aa5450 |
14 | 4d5d53d43c3 |
15 | 274a3383d33 |
hex | 14df8fb3107 |
1434401321223 has 32 divisors (see below), whose sum is σ = 2107707906304. Its totient is φ = 862116659712.
The previous prime is 1434401321203. The next prime is 1434401321237. The reversal of 1434401321223 is 3221231044341.
It is not a de Polignac number, because 1434401321223 - 29 = 1434401320711 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1434401321203) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 32852415 + ... + 32896047.
It is an arithmetic number, because the mean of its divisors is an integer number (65865872072).
Almost surely, 21434401321223 is an apocalyptic number.
1434401321223 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
1434401321223 is a deficient number, since it is larger than the sum of its proper divisors (673306585081).
1434401321223 is a wasteful number, since it uses less digits than its factorization.
1434401321223 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 63295.
The product of its (nonzero) digits is 13824, while the sum is 30.
Adding to 1434401321223 its reverse (3221231044341), we get a palindrome (4655632365564).
The spelling of 1434401321223 in words is "one trillion, four hundred thirty-four billion, four hundred one million, three hundred twenty-one thousand, two hundred twenty-three".
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