Base | Representation |
---|---|
bin | 10100110111111010001… |
… | …011000110000111011111 |
3 | 12002010111021210010201022 |
4 | 110313322023012013133 |
5 | 142000143324302312 |
6 | 3014544123034355 |
7 | 205430204031056 |
oct | 24677213060737 |
9 | 5063437703638 |
10 | 1434421322207 |
11 | 503375494115 |
12 | 1b200096b9bb |
13 | a535ac89153 |
14 | 4d5d7d1d39d |
15 | 274a4ed5172 |
hex | 14dfa2c61df |
1434421322207 has 2 divisors, whose sum is σ = 1434421322208. Its totient is φ = 1434421322206.
The previous prime is 1434421322183. The next prime is 1434421322237. The reversal of 1434421322207 is 7022231244341.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1434421322207 - 220 = 1434420273631 is a prime.
It is a super-2 number, since 2×14344213222072 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1434421322237) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 717210661103 + 717210661104.
It is an arithmetic number, because the mean of its divisors is an integer number (717210661104).
Almost surely, 21434421322207 is an apocalyptic number.
1434421322207 is a deficient number, since it is larger than the sum of its proper divisors (1).
1434421322207 is an equidigital number, since it uses as much as digits as its factorization.
1434421322207 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 64512, while the sum is 35.
Adding to 1434421322207 its reverse (7022231244341), we get a palindrome (8456652566548).
The spelling of 1434421322207 in words is "one trillion, four hundred thirty-four billion, four hundred twenty-one million, three hundred twenty-two thousand, two hundred seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.068 sec. • engine limits •