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1434421324093 is a prime number
BaseRepresentation
bin10100110111111010001…
…011000110100100111101
312002010111021210020022011
4110313322023012210331
5142000143324332333
63014544123051221
7205430204036422
oct24677213064475
95063437706264
101434421324093
1150337549557a
121b2000970b11
13a535ac89c74
144d5d7d1dd49
15274a4ed59cd
hex14dfa2c693d

1434421324093 has 2 divisors, whose sum is σ = 1434421324094. Its totient is φ = 1434421324092.

The previous prime is 1434421324087. The next prime is 1434421324103. The reversal of 1434421324093 is 3904231244341.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1369936816249 + 64484507844 = 1170443^2 + 253938^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1434421324093 is a prime.

It is a super-3 number, since 3×14344213240933 (a number of 37 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1434421304093) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 717210662046 + 717210662047.

It is an arithmetic number, because the mean of its divisors is an integer number (717210662047).

Almost surely, 21434421324093 is an apocalyptic number.

It is an amenable number.

1434421324093 is a deficient number, since it is larger than the sum of its proper divisors (1).

1434421324093 is an equidigital number, since it uses as much as digits as its factorization.

1434421324093 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 248832, while the sum is 40.

The spelling of 1434421324093 in words is "one trillion, four hundred thirty-four billion, four hundred twenty-one million, three hundred twenty-four thousand, ninety-three".