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1434421324103 is a prime number
BaseRepresentation
bin10100110111111010001…
…011000110100101000111
312002010111021210020022112
4110313322023012211013
5142000143324332403
63014544123051235
7205430204036435
oct24677213064507
95063437706275
101434421324103
11503375495589
121b2000970b1b
13a535ac89c81
144d5d7d1dd55
15274a4ed59d8
hex14dfa2c6947

1434421324103 has 2 divisors, whose sum is σ = 1434421324104. Its totient is φ = 1434421324102.

The previous prime is 1434421324093. The next prime is 1434421324151. The reversal of 1434421324103 is 3014231244341.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1434421324103 - 24 = 1434421324087 is a prime.

It is a super-3 number, since 3×14344213241033 (a number of 37 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1434421324103.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1434421324183) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 717210662051 + 717210662052.

It is an arithmetic number, because the mean of its divisors is an integer number (717210662052).

Almost surely, 21434421324103 is an apocalyptic number.

1434421324103 is a deficient number, since it is larger than the sum of its proper divisors (1).

1434421324103 is an equidigital number, since it uses as much as digits as its factorization.

1434421324103 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 27648, while the sum is 32.

Adding to 1434421324103 its reverse (3014231244341), we get a palindrome (4448652568444).

The spelling of 1434421324103 in words is "one trillion, four hundred thirty-four billion, four hundred twenty-one million, three hundred twenty-four thousand, one hundred three".