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1434432334021 is a prime number
BaseRepresentation
bin10100110111111010110…
…101000110100011000101
312002010112001111121002021
4110313322311012203011
5142000204134142041
63014545155043141
7205430366443351
oct24677265064305
95063461447067
101434432334021
11503380725495
121b20045a04b1
13a536034340b
144d5d9588461
15274a5e5ccd1
hex14dfad468c5

1434432334021 has 2 divisors, whose sum is σ = 1434432334022. Its totient is φ = 1434432334020.

The previous prime is 1434432334009. The next prime is 1434432334051. The reversal of 1434432334021 is 1204332344341.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1068515016100 + 365917317921 = 1033690^2 + 604911^2 .

It is a cyclic number.

It is not a de Polignac number, because 1434432334021 - 213 = 1434432325829 is a prime.

It is a super-2 number, since 2×14344323340212 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1434432334051) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 717216167010 + 717216167011.

It is an arithmetic number, because the mean of its divisors is an integer number (717216167011).

Almost surely, 21434432334021 is an apocalyptic number.

It is an amenable number.

1434432334021 is a deficient number, since it is larger than the sum of its proper divisors (1).

1434432334021 is an equidigital number, since it uses as much as digits as its factorization.

1434432334021 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 82944, while the sum is 34.

Adding to 1434432334021 its reverse (1204332344341), we get a palindrome (2638764678362).

The spelling of 1434432334021 in words is "one trillion, four hundred thirty-four billion, four hundred thirty-two million, three hundred thirty-four thousand, twenty-one".