Base | Representation |
---|---|
bin | 11010101101111111… |
… | …00101010100100111 |
3 | 1101000200112112211112 |
4 | 31112333211110213 |
5 | 213334132113112 |
6 | 10331214255235 |
7 | 1015316322335 |
oct | 152677452447 |
9 | 41020475745 |
10 | 14344410407 |
11 | 60a1055938 |
12 | 2943ab751b |
13 | 1477a88b12 |
14 | 9a112ab55 |
15 | 58e4b5a22 |
hex | 356fe5527 |
14344410407 has 2 divisors, whose sum is σ = 14344410408. Its totient is φ = 14344410406.
The previous prime is 14344410403. The next prime is 14344410461. The reversal of 14344410407 is 70401444341.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14344410407 - 22 = 14344410403 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14344410401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7172205203 + 7172205204.
It is an arithmetic number, because the mean of its divisors is an integer number (7172205204).
Almost surely, 214344410407 is an apocalyptic number.
14344410407 is a deficient number, since it is larger than the sum of its proper divisors (1).
14344410407 is an equidigital number, since it uses as much as digits as its factorization.
14344410407 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 21504, while the sum is 32.
Adding to 14344410407 its reverse (70401444341), we get a palindrome (84745854748).
The spelling of 14344410407 in words is "fourteen billion, three hundred forty-four million, four hundred ten thousand, four hundred seven".
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