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1434456505451 is a prime number
BaseRepresentation
bin10100110111111100010…
…001010011110001101011
312002010120201222122001102
4110313330101103301223
5142000231331133301
63014551421112015
7205431112055114
oct24677421236153
95063521878042
101434456505451
11503393334882
121b20106b860b
13a5365357438
144d5dc87b20b
15274a8134b6b
hex14dfc453c6b

1434456505451 has 2 divisors, whose sum is σ = 1434456505452. Its totient is φ = 1434456505450.

The previous prime is 1434456505439. The next prime is 1434456505453. The reversal of 1434456505451 is 1545056544341.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1434456505451 - 210 = 1434456504427 is a prime.

Together with 1434456505453, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 1434456505396 and 1434456505405.

It is not a weakly prime, because it can be changed into another prime (1434456505453) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 717228252725 + 717228252726.

It is an arithmetic number, because the mean of its divisors is an integer number (717228252726).

Almost surely, 21434456505451 is an apocalyptic number.

1434456505451 is a deficient number, since it is larger than the sum of its proper divisors (1).

1434456505451 is an equidigital number, since it uses as much as digits as its factorization.

1434456505451 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2880000, while the sum is 47.

The spelling of 1434456505451 in words is "one trillion, four hundred thirty-four billion, four hundred fifty-six million, five hundred five thousand, four hundred fifty-one".