Base | Representation |
---|---|
bin | 1101000011000000100111… |
… | …0100000110111100011101 |
3 | 1212210101212111002012222021 |
4 | 3100300021310012330131 |
5 | 3340013241442023032 |
6 | 50302055412220141 |
7 | 3010263165124366 |
oct | 320601164067435 |
9 | 55711774065867 |
10 | 14345355423517 |
11 | 4630916176978 |
12 | 173828660a651 |
13 | 8009b84c8661 |
14 | 37846711cb6d |
15 | 19d250306097 |
hex | d0c09d06f1d |
14345355423517 has 2 divisors, whose sum is σ = 14345355423518. Its totient is φ = 14345355423516.
The previous prime is 14345355423461. The next prime is 14345355423559. The reversal of 14345355423517 is 71532455354341.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13510189735641 + 835165687876 = 3675621^2 + 913874^2 .
It is a cyclic number.
It is not a de Polignac number, because 14345355423517 - 231 = 14343207939869 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14345355426517) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7172677711758 + 7172677711759.
It is an arithmetic number, because the mean of its divisors is an integer number (7172677711759).
Almost surely, 214345355423517 is an apocalyptic number.
It is an amenable number.
14345355423517 is a deficient number, since it is larger than the sum of its proper divisors (1).
14345355423517 is an equidigital number, since it uses as much as digits as its factorization.
14345355423517 is an evil number, because the sum of its binary digits is even.
The product of its digits is 15120000, while the sum is 52.
The spelling of 14345355423517 in words is "fourteen trillion, three hundred forty-five billion, three hundred fifty-five million, four hundred twenty-three thousand, five hundred seventeen".
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