14353141314013 has 2 divisors, whose sum is σ = 14353141314014. Its totient is φ = 14353141314012.

The previous prime is 14353141313989. The next prime is 14353141314019. The reversal of 14353141314013 is 31041314135341.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12746235214969 + 1606906099044 = 3570187^2 + 1267638^2 .

It is an emirp because it is prime and its reverse (31041314135341) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14353141314013 - 2²¹ = 14353139216861 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 14353141314013.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14353141314019) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7176570657006 + 7176570657007.

It is an arithmetic number, because the mean of its divisors is an integer number (7176570657007).

Almost surely, 2^{14353141314013} is an apocalyptic number.

It is an amenable number.

14353141314013 is a deficient number, since it is larger than the sum of its proper divisors (1).

14353141314013 is an equidigital number, since it uses as much as digits as its factorization.

14353141314013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 25920, while the sum is 34.

Adding to 14353141314013 its reverse (31041314135341), we get a palindrome (45394455449354).

The spelling of 14353141314013 in words is "fourteen trillion, three hundred fifty-three billion, one hundred forty-one million, three hundred fourteen thousand, thirteen".