14354125231 has 2 divisors, whose sum is σ = 14354125232. Its totient is φ = 14354125230.

The previous prime is 14354125213. The next prime is 14354125237. The reversal of 14354125231 is 13252145341.

Together with previous prime (14354125213) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 14354125231 - 2⁵ = 14354125199 is a prime.

It is a super-2 number, since 2×14354125231² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 14354125193 and 14354125202.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14354125237) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7177062615 + 7177062616.

It is an arithmetic number, because the mean of its divisors is an integer number (7177062616).

Almost surely, 2^14354125231 is an apocalyptic number.

14354125231 is a deficient number, since it is larger than the sum of its proper divisors (1).

14354125231 is an equidigital number, since it uses as much as digits as its factorization.

14354125231 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 14400, while the sum is 31.

The spelling of 14354125231 in words is "fourteen billion, three hundred fifty-four million, one hundred twenty-five thousand, two hundred thirty-one".