Search a number
-
+
14354125213 is a prime number
BaseRepresentation
bin11010101111001001…
…01001000110011101
31101001100211010001011
431113210221012131
5213344124001323
610332202415221
71015465023361
oct152744510635
941040733034
1014354125213
1160a65907aa
122947201511
131479aaa91c
149a25392a1
1559028420d
hex35792919d

14354125213 has 2 divisors, whose sum is σ = 14354125214. Its totient is φ = 14354125212.

The previous prime is 14354125211. The next prime is 14354125231. The reversal of 14354125213 is 31252145341.

Together with next prime (14354125231) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13322238084 + 1031887129 = 115422^2 + 32123^2 .

It is a cyclic number.

It is not a de Polignac number, because 14354125213 - 21 = 14354125211 is a prime.

Together with 14354125211, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14354125211) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7177062606 + 7177062607.

It is an arithmetic number, because the mean of its divisors is an integer number (7177062607).

Almost surely, 214354125213 is an apocalyptic number.

It is an amenable number.

14354125213 is a deficient number, since it is larger than the sum of its proper divisors (1).

14354125213 is an equidigital number, since it uses as much as digits as its factorization.

14354125213 is an evil number, because the sum of its binary digits is even.

The product of its digits is 14400, while the sum is 31.

The spelling of 14354125213 in words is "fourteen billion, three hundred fifty-four million, one hundred twenty-five thousand, two hundred thirteen".