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14354145551423 is a prime number
BaseRepresentation
bin1101000011100001010110…
…1111110010010000111111
31212211020120002020222121002
43100320111233302100333
53340134242230121143
650310111535200515
73011024052023426
oct320702557622077
955736502228532
1014354145551423
114634616a52097
121739b1a37613b
13801789646082
14378a5c7022bd
1519d5b6d785b8
hexd0e15bf243f

14354145551423 has 2 divisors, whose sum is σ = 14354145551424. Its totient is φ = 14354145551422.

The previous prime is 14354145551411. The next prime is 14354145551429. The reversal of 14354145551423 is 32415554145341.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 14354145551423 - 24 = 14354145551407 is a prime.

It is a super-2 number, since 2×143541455514232 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14354145551429) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7177072775711 + 7177072775712.

It is an arithmetic number, because the mean of its divisors is an integer number (7177072775712).

Almost surely, 214354145551423 is an apocalyptic number.

14354145551423 is a deficient number, since it is larger than the sum of its proper divisors (1).

14354145551423 is an equidigital number, since it uses as much as digits as its factorization.

14354145551423 is an evil number, because the sum of its binary digits is even.

The product of its digits is 2880000, while the sum is 47.

Adding to 14354145551423 its reverse (32415554145341), we get a palindrome (46769699696764).

The spelling of 14354145551423 in words is "fourteen trillion, three hundred fifty-four billion, one hundred forty-five million, five hundred fifty-one thousand, four hundred twenty-three".