Base | Representation |
---|---|
bin | 10100111001110010011… |
… | …111101111011111101101 |
3 | 12002022200222021121201202 |
4 | 110321302133233133231 |
5 | 142013312120003433 |
6 | 3015520314215245 |
7 | 205531215355361 |
oct | 24716237573755 |
9 | 5068628247652 |
10 | 1436440000493 |
11 | 504210a28a83 |
12 | 1b2484a24525 |
13 | a55c0273144 |
14 | 4d74a07b2a1 |
15 | 27572336ee8 |
hex | 14e727ef7ed |
1436440000493 has 2 divisors, whose sum is σ = 1436440000494. Its totient is φ = 1436440000492.
The previous prime is 1436440000487. The next prime is 1436440000547. The reversal of 1436440000493 is 3940000446341.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1430602582084 + 5837418409 = 1196078^2 + 76403^2 .
It is a cyclic number.
It is not a de Polignac number, because 1436440000493 - 222 = 1436435806189 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1436440200493) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 718220000246 + 718220000247.
It is an arithmetic number, because the mean of its divisors is an integer number (718220000247).
Almost surely, 21436440000493 is an apocalyptic number.
It is an amenable number.
1436440000493 is a deficient number, since it is larger than the sum of its proper divisors (1).
1436440000493 is an equidigital number, since it uses as much as digits as its factorization.
1436440000493 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 124416, while the sum is 38.
The spelling of 1436440000493 in words is "one trillion, four hundred thirty-six billion, four hundred forty million, four hundred ninety-three", and thus it is an aban number.
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