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14374503431 is a prime number
BaseRepresentation
bin11010110001100100…
…11000010000000111
31101002210011102200222
431120302120100013
5213414333102211
610334211254555
71016133156161
oct153062302007
941083142628
1014374503431
11610703a202
122951baa45b
131481094242
149a5121931
15591e5c1db
hex358c98407

14374503431 has 2 divisors, whose sum is σ = 14374503432. Its totient is φ = 14374503430.

The previous prime is 14374503421. The next prime is 14374503433. The reversal of 14374503431 is 13430547341.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14374503431 is a prime.

It is a super-2 number, since 2×143745034312 (a number of 21 digits) contains 22 as substring.

Together with 14374503433, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 14374503391 and 14374503400.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14374503433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7187251715 + 7187251716.

It is an arithmetic number, because the mean of its divisors is an integer number (7187251716).

Almost surely, 214374503431 is an apocalyptic number.

14374503431 is a deficient number, since it is larger than the sum of its proper divisors (1).

14374503431 is an equidigital number, since it uses as much as digits as its factorization.

14374503431 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 60480, while the sum is 35.

The spelling of 14374503431 in words is "fourteen billion, three hundred seventy-four million, five hundred three thousand, four hundred thirty-one".