Base | Representation |
---|---|
bin | 11010110010010010… |
… | …11010000110001111 |
3 | 1101010012112010201211 |
4 | 31121021122012033 |
5 | 213422404242203 |
6 | 10334544515251 |
7 | 1016235401323 |
oct | 153111320617 |
9 | 41105463654 |
10 | 14380540303 |
11 | 610a492858 |
12 | 295401bb27 |
13 | 14823c8c5c |
14 | 9a5c53983 |
15 | 592750c6d |
hex | 35925a18f |
14380540303 has 2 divisors, whose sum is σ = 14380540304. Its totient is φ = 14380540302.
The previous prime is 14380540301. The next prime is 14380540373. The reversal of 14380540303 is 30304508341.
14380540303 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is an emirp because it is prime and its reverse (30304508341) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 14380540303 - 21 = 14380540301 is a prime.
Together with 14380540301, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14380540301) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7190270151 + 7190270152.
It is an arithmetic number, because the mean of its divisors is an integer number (7190270152).
Almost surely, 214380540303 is an apocalyptic number.
14380540303 is a deficient number, since it is larger than the sum of its proper divisors (1).
14380540303 is an equidigital number, since it uses as much as digits as its factorization.
14380540303 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 17280, while the sum is 31.
The spelling of 14380540303 in words is "fourteen billion, three hundred eighty million, five hundred forty thousand, three hundred three".
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