Base | Representation |
---|---|
bin | 1101000101111001010011… |
… | …0000101011111110011111 |
3 | 1212222010211111122121012102 |
4 | 3101132110300223332133 |
5 | 3341321304341344103 |
6 | 50340535021155315 |
7 | 3013666546225532 |
oct | 321362460537637 |
9 | 55863744577172 |
10 | 14394931199903 |
11 | 464a9464294a1 |
12 | 1745a013bbb3b |
13 | 8055893c5097 |
14 | 37aa0b380a19 |
15 | 19e6a27eee88 |
hex | d1794c2bf9f |
14394931199903 has 2 divisors, whose sum is σ = 14394931199904. Its totient is φ = 14394931199902.
The previous prime is 14394931199893. The next prime is 14394931200053. The reversal of 14394931199903 is 30999113949341.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14394931199903 - 28 = 14394931199647 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 14394931199903.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14394931192903) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7197465599951 + 7197465599952.
It is an arithmetic number, because the mean of its divisors is an integer number (7197465599952).
Almost surely, 214394931199903 is an apocalyptic number.
14394931199903 is a deficient number, since it is larger than the sum of its proper divisors (1).
14394931199903 is an equidigital number, since it uses as much as digits as its factorization.
14394931199903 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 25509168, while the sum is 65.
The spelling of 14394931199903 in words is "fourteen trillion, three hundred ninety-four billion, nine hundred thirty-one million, one hundred ninety-nine thousand, nine hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •