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14394931200053 is a prime number
BaseRepresentation
bin1101000101111001010011…
…0000101100000000110101
31212222010211111122121101222
43101132110300230000311
53341321304341400203
650340535021200125
73013666546226135
oct321362460540065
955863744577358
1014394931200053
11464a946429618
121745a01400045
138055893c5181
1437aa0b380ac5
1519e6a2800038
hexd1794c2c035

14394931200053 has 2 divisors, whose sum is σ = 14394931200054. Its totient is φ = 14394931200052.

The previous prime is 14394931199903. The next prime is 14394931200077. The reversal of 14394931200053 is 35000213949341.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12711520963684 + 1683410236369 = 3565322^2 + 1297463^2 .

It is a cyclic number.

It is not a de Polignac number, because 14394931200053 - 218 = 14394930937909 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14394931199977 and 14394931200013.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14394931200553) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7197465600026 + 7197465600027.

It is an arithmetic number, because the mean of its divisors is an integer number (7197465600027).

Almost surely, 214394931200053 is an apocalyptic number.

It is an amenable number.

14394931200053 is a deficient number, since it is larger than the sum of its proper divisors (1).

14394931200053 is an equidigital number, since it uses as much as digits as its factorization.

14394931200053 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 349920, while the sum is 44.

The spelling of 14394931200053 in words is "fourteen trillion, three hundred ninety-four billion, nine hundred thirty-one million, two hundred thousand, fifty-three".