Base | Representation |
---|---|
bin | 11010110100100000… |
… | …10111110011101111 |
3 | 1101011111112021001012 |
4 | 31122100113303233 |
5 | 213442140040101 |
6 | 10340451335435 |
7 | 1016552461121 |
oct | 153220276357 |
9 | 41144467035 |
10 | 14399143151 |
11 | 6119a39408 |
12 | 295a2b157b |
13 | 1486210463 |
14 | 9a84d7211 |
15 | 5941c7bbb |
hex | 35a417cef |
14399143151 has 2 divisors, whose sum is σ = 14399143152. Its totient is φ = 14399143150.
The previous prime is 14399143127. The next prime is 14399143153. The reversal of 14399143151 is 15134199341.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14399143151 - 214 = 14399126767 is a prime.
Together with 14399143153, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 14399143099 and 14399143108.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14399143153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7199571575 + 7199571576.
It is an arithmetic number, because the mean of its divisors is an integer number (7199571576).
Almost surely, 214399143151 is an apocalyptic number.
14399143151 is a deficient number, since it is larger than the sum of its proper divisors (1).
14399143151 is an equidigital number, since it uses as much as digits as its factorization.
14399143151 is an evil number, because the sum of its binary digits is even.
The product of its digits is 58320, while the sum is 41.
The spelling of 14399143151 in words is "fourteen billion, three hundred ninety-nine million, one hundred forty-three thousand, one hundred fifty-one".
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