1440001117 has 2 divisors, whose sum is σ = 1440001118. Its totient is φ = 1440001116.

The previous prime is 1440001111. The next prime is 1440001153. The reversal of 1440001117 is 7111000441.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1439519481 + 481636 = 37941^2 + 694^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1440001117 is a prime.

It is a super-2 number, since 2×1440001117² = 4147206433922495378, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1440001094 and 1440001103.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1440001111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 720000558 + 720000559.

It is an arithmetic number, because the mean of its divisors is an integer number (720000559).

Almost surely, 2^1440001117 is an apocalyptic number.

It is an amenable number.

1440001117 is a deficient number, since it is larger than the sum of its proper divisors (1).

1440001117 is an equidigital number, since it uses as much as digits as its factorization.

1440001117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 112, while the sum is 19.

The square root of 1440001117 is about 37947.3466397850. The cubic root of 1440001117 is about 1129.2435266397.

Adding to 1440001117 its reverse (7111000441), we get a palindrome (8551001558).

The spelling of 1440001117 in words is "one billion, four hundred forty million, one thousand, one hundred seventeen".